United States Calculus 2 - Infinite Series

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Homework Statement



Determine how many terms of the following convergent series must be summed to be sure that the remainder is less than 10^-5. Although you do not need it, the exact value of the series is given.

ln(128) = 7*sum[k=1,inf] of (-1)^(k+1)/k

Homework Equations





3. The Attempt at a Solution [/b

| ln(128) - 7*sum[k=1,n] of (-1)^(k+1)/k | < 1/10,000
subtracted ln(128) from both sides
|-7*sum[k=1,n] of (-1)^(k+1)/k | < 1/10,000 - ln(128)
simplified the negative on the left hand side and absolute value
7*sum[k=1,n] of 1/k < 1/10,000 - ln(128)
divided through by 7
sum[k=1,n] of 1/k < 1/70,000 - ln(128)/7

I'm unsure were to go from here, thank you for any help you can provide me.
 
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GreenPrint said:

Homework Statement



Determine how many terms of the following convergent series must be summed to be sure that the remainder is less than 10^-5. Although you do not need it, the exact value of the series is given.

ln(128) = 7*sum[k=1,inf] of (-1)^(k+1)/k

Homework Equations





3. The Attempt at a Solution [/b

| ln(128) - 7*sum[k=1,n] of (-1)^(k+1)/k | < 1/10,000
subtracted ln(128) from both sides
|-7*sum[k=1,n] of (-1)^(k+1)/k | < 1/10,000 - ln(128)
simplified the negative on the left hand side and absolute value
7*sum[k=1,n] of 1/k < 1/10,000 - ln(128)
divided through by 7
sum[k=1,n] of 1/k < 1/70,000 - ln(128)/7

I'm unsure were to go from here, thank you for any help you can provide me.

There's a remainder theorem for alternating series. Take a look at it.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...

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