Unknown operator that performs action on a matrix

  • Thread starter Thread starter 81THE1
  • Start date Start date
  • Tags Tags
    Matrix Operator
81THE1
Messages
3
Reaction score
0

Homework Statement



write the matrices M which, when acting on A, divides the second row by a factor a, while leaving the other rows unchanged


Homework Equations



I solved a question on the Gauss-Jordan inversion which showed converting the matrix to the identity would also turn the identity into the inverse; I was thinking for this problem I would take the inversion of A and multiply it by my desired vector to give my answer? Is there a simpler way to do this? assuming my way is correct...


The Attempt at a Solution



Thanks
 
Physics news on Phys.org
If by 'acting on' you mean the product M*A, then it's a lot easier than you think. The identity matrix doesn't change A at all. Change one entry in the identity matrix so it does what you want.
 
This is where I am struggling...

I can not seem to find the term to change, and rather than guessing at a solution I want to be able to solve the problem as there is a part b also that will require the same methodology.

A|x> = <alpha| ... If i were to multiply both sides by the inverse of A, it would appear that |x> would be left and that would be my answer, is this correct? If so, it seems like solving the inverse of A would be painfully long. Do you agree, or can i simply just take its transpose?
 
I see my problem now I think...I was going A * M, not M * A...

If I want to change the second row, now all I have to do is manipulate the second term of the identity matrix to be 1/alpha.

When I reversed them, switching the second one was manipulating the columns...not the rows.

Thanks for your response!
 
Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...
Back
Top