Use Green's Theorem to evaluate the line integral

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SUMMARY

This discussion focuses on using Green's Theorem to evaluate the line integral of the form (integral over C) (2x dy - 3y dx) over a square defined by the vertices (0,2), (2,0), (-2,0), and (0,-2). The participants emphasize the importance of determining the correct limits for the double integral, suggesting two approaches: applying a transformation to rotate the area into a square or approximating the area with vertical rectangles. The discussion highlights the necessity of understanding the boundaries for both x and y coordinates when setting up the double integral.

PREREQUISITES
  • Understanding of Green's Theorem
  • Familiarity with double integrals
  • Knowledge of coordinate transformations
  • Ability to visualize geometric shapes in calculus
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  • Study the application of Green's Theorem in various contexts
  • Practice setting up double integrals with non-rectangular regions
  • Learn about coordinate transformations in multivariable calculus
  • Explore methods for approximating areas using Riemann sums
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Students and educators in calculus, particularly those focusing on vector calculus and line integrals, as well as anyone looking to deepen their understanding of Green's Theorem and its applications in evaluating integrals over complex regions.

jlmac2001
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Problem:

Use Green's Theorem to evaluate the line integral:

(integral over C) (2x dy - 3y dx)

where C is a square with the vertices (0,2) (2,0) (-2,0) and (0, -2) and is transversed counterclockwise.

Answer:

will the double integral be -1 dydx? What will they go from? Will it be from -2 to 2 and 0 to 2
 
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Answer: write down Green's theorem. comare it to what you have in the problem, decide which terms are in correspondence, and then do what you need to. the area is a diamond, your notional limits would give you a square.

is the problem really that you're not sure about the limits in double integrals?

two ways round this. 1, apply a transform to rotate the area to get a square. 2, thnk about it like this - imagine drawing vertical rectangles to apporximate the area, ie do y first, y goes from the lower boundary to the top, write the lower and upper boundary as functions of x - you will need to do two cases here for x negative and positive - those are the limits for y. then think about the x direction, which is, if you like, how are these rectangles positioned - here they start at x=-2 and end at x=2, so those will be the x limits.
 
I have the same problem with the limits, how is it that you are able to approximate it as two rectangles?
Also, if you use the limits 2 and -2 for the x, I am unable to work how how you would find the limits for the y.
 

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