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- Thread starter Ninja_IPGO
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- #1

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- #2

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- #4

vk6kro

Science Advisor

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You can work out the voltages and currents with just a calculator and then at least you will know if what you are getting makes sense when you do the node analysis.

I would add a LOT more explanation and diagrams. I couldn't see where most of that was coming from and I shouldn't have to be guessing.

Draw the part of the diagram you are dealing with and justify each step before you go on.

- #5

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[tex] R_{eq}^{-1} = 2500^{-1} +500^{-1}+1000^{-1} =.0034 [/tex]

and

[tex] .0034^{-1}=294.1176471=\frac{5000}{17} [/tex]

how'd you get 263?

@Ninja IPGO, I am currently taking electrical fundamentals for the first time (i dont know what class you are taking but it looks much the same) and we can use any 'tools' we have to solve any of the problems. Why would there be a problem combining resistors in this problem? It is what you would do in a similar real life situation.

edit: what i really meant is if the problem says 'use mesh analysis to solve for i0 an v0' we could most certainly combine resistors to solve the problem, just not use node voltage. I don't see using voltage, current division or series/parallel combination as 'not using the method specified'.

- #6

vk6kro

Science Advisor

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(1500 + 1000), 2500, 500, 1000 ohms

And this gives 263.158 ohms.

You put this in series with the 750 ohms across 100 volts to get the voltage at node b.

Then you have 2500 ohms in series with 1000 ohms across this voltage to get the voltage at node c.

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- #8

vk6kro

Science Advisor

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You have 750 ohms then in series with 263 ohms across 100 volts. It is easy to work out the voltage across the 263 ohms. (100 times 263/1013)

Now that you know this voltage, it is across all the resistors in parallel including the two that are in series with each other.

So, they form a new divider and you can work out the voltage across the 1000 ohm resistor.

(100 times 263/1013) times 1000/2500.

It is so easy, you just write down the answers off the calculator.

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- #10

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i redid the problem there was a few algebraic errors but the method i used is correct

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