- #1
Gotbread
- 3
- 0
Hello everyone!
I have seen several DIY projects which successfully gathered heavy water
from normal water. For example Cody from codys lab used electrolysis
to "enrich" the water. This however is a messy process.
So i became curious, if this can be done easier by centrifugation.
Based on these data http://www1.lsbu.ac.uk/water/water_properties.html
around 1 in 6600 water molecules are heavy water (HDO). This would
have a density of ~1050kg/m³ compared to ~996kg/m³. This is not enough
to separate them under normal gravity but maybe this difference is enough
to be able to separate them in a centrifuge.
To get a feel for the forces needed, i want to calculate this. But here
is where i got stuck.
First, we assume a cylindrical centrifuge, spinning at a constant RPM.
We also assume that the system has reached a steady state so in the
frame of reference of the spinning liquid, nothing is moving. In that
frame, a fictitious force depending on the radius F(r) will act on the
liquid. Since the system is highly symmetric, it should be equivalent
to looking at only a 1D column along the radius.
In this steady state, the movement of particles due to the centrifugal
action and the movement due to diffusion will balance. Looking again at
the data table we find the diffusion coefficients of H2O and HDO, which
are (in SI) 2.299e-7 m²/s and 2.34e-7 m²/s respectively.
Here is my first confusion: the diffusion coefficient requires two
substances, is the second substance "normal water" (normal mixture of
H2O and HDO) ?
Second, to calculate the distribution, i am looking for a PDE i can
integrate numerically. I found the diffusion equation:
\frac{\partial \phi(r, t)}{\partial t} = \nabla \cdot \big[ D(r,t))\nabla \phi(r,t) \big]
with \phi being the density and D the collective diffusion coefficient.
(Can i assume the collective diffusion coefficient is the density weighted
average of the individual diffusion coefficients?)
Obviously, this equation does not include the radial force or the resultant
pressure.
I hope i can get around using the full navier-stokes equations, as they are
quite complicated. Is there a simpler form i can use? Essentially i am looking
for a 1D PDE.
I have seen several DIY projects which successfully gathered heavy water
from normal water. For example Cody from codys lab used electrolysis
to "enrich" the water. This however is a messy process.
So i became curious, if this can be done easier by centrifugation.
Based on these data http://www1.lsbu.ac.uk/water/water_properties.html
around 1 in 6600 water molecules are heavy water (HDO). This would
have a density of ~1050kg/m³ compared to ~996kg/m³. This is not enough
to separate them under normal gravity but maybe this difference is enough
to be able to separate them in a centrifuge.
To get a feel for the forces needed, i want to calculate this. But here
is where i got stuck.
First, we assume a cylindrical centrifuge, spinning at a constant RPM.
We also assume that the system has reached a steady state so in the
frame of reference of the spinning liquid, nothing is moving. In that
frame, a fictitious force depending on the radius F(r) will act on the
liquid. Since the system is highly symmetric, it should be equivalent
to looking at only a 1D column along the radius.
In this steady state, the movement of particles due to the centrifugal
action and the movement due to diffusion will balance. Looking again at
the data table we find the diffusion coefficients of H2O and HDO, which
are (in SI) 2.299e-7 m²/s and 2.34e-7 m²/s respectively.
Here is my first confusion: the diffusion coefficient requires two
substances, is the second substance "normal water" (normal mixture of
H2O and HDO) ?
Second, to calculate the distribution, i am looking for a PDE i can
integrate numerically. I found the diffusion equation:
\frac{\partial \phi(r, t)}{\partial t} = \nabla \cdot \big[ D(r,t))\nabla \phi(r,t) \big]
with \phi being the density and D the collective diffusion coefficient.
(Can i assume the collective diffusion coefficient is the density weighted
average of the individual diffusion coefficients?)
Obviously, this equation does not include the radial force or the resultant
pressure.
I hope i can get around using the full navier-stokes equations, as they are
quite complicated. Is there a simpler form i can use? Essentially i am looking
for a 1D PDE.