Using free fall acceleration to find another acceleration

AI Thread Summary
The discussion revolves around calculating the acceleration of a prototype automobile during a controlled stop from 100 km/h to zero over a distance of 41 meters, expressed as a fraction of free-fall acceleration (g = 9.81 m/s²). The kinematic equation used is v² = Vo² + 2ax, leading to an acceleration calculation of approximately -9.41 m/s². This value was then converted to a fraction of g, resulting in approximately 0.96g. However, the final acceleration should be negative to indicate deceleration, and attention to significant figures is also necessary for accuracy. The user seeks clarification on their errors in the calculation process.
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Homework Statement



A test of the prototype of a new automobile
shows that the minimum distance for a con-
trolled stop from 100 km/h to zero is 41 m.
Find the acceleration, assuming it to be
constant as a fraction of the free-fall accel-
eration. The acceleration due to gravity is
9.81 m/s2.
Answer in units of g.


Homework Equations



Kinematics equations


The Attempt at a Solution



I'm actually unsure how to even begin this problem. The statement has me confused, such as what they mean by "a fraction of the free-fall acceleration."
 
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It means 9.8 m/s^2 would be 1g, 19.6 m/s^2 would be 2g, etc.

Do you know any kinematic equation that relates final speed, initial speed, acceleration, and distance?
 
What I used with your advice was this equation:

v^2 = Vo^2 + 2ax -> a = v^2 - vo^2 / 2x -> 0 - (27.778 m/s^2) / 2(41m) = -9.4098

From here I did this equation as a fraction of the free fall acceleration:

-9.4098 m/s^2 / -9.80m/s^2 -> A = .9602g.

Whatever I might have done, I got the question wrong. Can you maybe help me elaborate on my errors?
 
Your methodology is okay. The resulting acceleration value, whether or not in units of g, should still be negative. You might also want to pay attention to the number of significant figures that are warranted.
 
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