Using Henry's law to calculate ammonia concentration?

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SUMMARY

This discussion focuses on calculating the concentration of ammonia in the air above a 5% ammonia solution (2.7 M) in a closed 20-liter chamber at 40°C using Henry's Law. Participants emphasize the importance of understanding vapor pressures to perform this calculation accurately. Key resources provided include links to vapor pressure data and ammonia solution tables, which are essential for deriving the necessary values. The discussion highlights the need for precise unit conversion when referencing vapor pressures.

PREREQUISITES
  • Understanding of Henry's Law and its application in gas solubility calculations
  • Knowledge of vapor pressure concepts and how they relate to liquid solutions
  • Familiarity with ammonia solution properties and concentrations
  • Ability to perform unit conversions in scientific calculations
NEXT STEPS
  • Research "Henry's Law constants for ammonia" to find specific values for calculations
  • Study "vapor pressure of ammonia solutions" for relevant data tables
  • Learn about "unit conversion techniques" in chemistry for accurate calculations
  • Explore "applications of vapor pressure in gas-liquid equilibria" for broader context
USEFUL FOR

Chemists, environmental scientists, and anyone involved in gas solubility calculations or studying ammonia solutions will benefit from this discussion.

Hopper295
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TL;DR
How do I calculate the concentration of ammonia in air above a ammina solution of a known concentration
We have a closed chamber of 20 liters. The bottom of this chamber is filled with ammonia solution of 5% (=2,7M/liter). The solution temperature is controlled at 40°C

I would like to calculate the concentration of ammmonia in the chamber air, above the solution. It should be something with henry's law but I don't knwo how to do this...
An approximation would already be super...

Hope someone can help me, thanks!
 
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You'll want to learn about the concept of vapour pressures first.
 
Hi dr. nate,

To be honest I don't know much about this... :rolleyes:

can you explain some more what you mean?
 
Ok thanks. I was already trying to do it myself using googel, but this doesn't go so well.
I was actually hoping someone would find this easy and show me how to do it.
 

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