Using moment of inertia to get angular speed

AI Thread Summary
The discussion revolves around calculating the angular speed of a retracting pole after an astronaut inadvertently imparts an initial angular speed of 0.0500 radians per second. The problem involves a uniform rod transitioning from a length of 3.00 meters to 1.50 meters due to a catch slipping. The moment of inertia formulas for both lengths are referenced, but confusion arises regarding the correct application of these equations to find the final angular speed. The user is uncertain about the necessity of mass in the calculations and struggles with defining initial and final moments of inertia. Clarification on these concepts is needed to solve the problem accurately.
seiya5
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Homework Statement



Hiya boys,

Sorry i don't know how to proceed with this problem can anyone help me solve these two questions?

In preparation for building a space station, an astronaut removes a self-telescoping uniform rod from the cargo bay and releases it, not noticing that he gave it an angular speed of 0.0500 radians per second. The pole is 3.00 meters long. A catch slips, and the pole spring retracts it into a shorter 1.50 meter long uniform pole about a minute after the astronaut releases it.
Find the angular speed after the catch slips.

Homework Equations



I = mr^2/12 or mr^2/3

ω = v/r

The Attempt at a Solution



Iinitial = Ifinal
m (3^2)/12 = m (1.5^2)/12

m= do i need this?

(0.05)(x) = ω
 
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seiya5 said:
Iinitial = Ifinal
m (3^2)/12 = m (1.5^2)/12

What are Iinitial and Ifinal here? The eqn can't be right since it reduces to 4 = 1.
 
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