Using Multi-Variable Chain Rule to Prove Equation Involving z = f(x^2 + y^2)

Click For Summary

Homework Help Overview

The discussion revolves around proving an equation involving the function z = f(x^2 + y^2) using the multi-variable chain rule. Participants are exploring how to apply the chain rule in this context.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • The original poster seeks guidance on how to begin the proof, specifically regarding the computation of dz/dx and dz/dy, and whether to substitute values for x and y. Other participants discuss the application of the chain rule, with some suggesting the relationship between dz/dx and dg/dx.

Discussion Status

Participants are actively engaging with the problem, with some providing insights into the chain rule and its application. There is a mix of attempts to clarify the process and check assumptions, but no consensus has been reached on the complete approach.

Contextual Notes

There is an indication that participants are working within the constraints of homework rules, and some express uncertainty about notation, particularly regarding partial derivatives.

hangten1
Messages
5
Reaction score
0

Homework Statement


z = f (x^2 + y^2)
prove using multi var chain rule that

y * dz/dx - x * dz/dy = 0


Homework Equations





The Attempt at a Solution



honestly i just need to no how to start it then I am sure i could figure the rest out

so i would find dz/dx and dz/dy then what would x and y be? and do i substiude any values of x and y to prove it works?
 

Attachments

  • question.jpg
    question.jpg
    13.5 KB · Views: 439
Physics news on Phys.org
z=f(g(x,y)), where g(x,y)=x^2+y^2. Now what does the chain rule tell you about, say ∂z/∂x?
 
something like dz/dx = dz/dg dg/dx?

(d = that stupid partial sign)
 
hangten1 said:
something like dz/dx = dz/dg dg/dx?

(d = that stupid partial sign)

If you use the "Go Advanced" button below the message box, then you have a new message box with a set of symbols on the right. Find the stupid ' ∂ ' there !
 
hangten1 said:
something like dz/dx = dz/dg dg/dx?

(d = that stupid partial sign)

f is a function of one variable. You could also write ∂z/∂g as f'(g(x,y)). Now what's ∂g/∂x?
 
2x * 1?
 
Yes.

ehild
 
tys dick and ehild

think i got it
 

Similar threads

  • · Replies 4 ·
Replies
4
Views
1K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 9 ·
Replies
9
Views
3K
  • · Replies 10 ·
Replies
10
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K
Replies
4
Views
1K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 9 ·
Replies
9
Views
3K