Using polar coordinates to find the volume of the given solid

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SUMMARY

The discussion focuses on calculating the volume of a solid defined by the constraints of being inside the sphere described by the equation x² + y² + z² = 16 and outside the cylinder defined by x² + y² = 4. The correct approach involves using polar coordinates with a double integral, specifically integrating from θ = 0 to θ = 2π and r = 2 to r = 4. The integrand is correctly formulated as ((16 - r²)^(1/2))r (dr)(dθ), ensuring that the volume calculation excludes the region inside the cylinder.

PREREQUISITES
  • Understanding of polar coordinates in three-dimensional space
  • Familiarity with double integrals and their applications
  • Knowledge of spherical and cylindrical coordinate systems
  • Basic calculus concepts, particularly volume integration
NEXT STEPS
  • Study the application of polar coordinates in volume calculations
  • Learn about the conversion between Cartesian and polar coordinates
  • Explore advanced integration techniques for calculating volumes of solids
  • Investigate the use of triple integrals in spherical coordinates
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Students and professionals in mathematics, physics, and engineering who are involved in volume calculations of solids using polar coordinates.

serg_yegi
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1. Use polar coordinates to find the volume of the given solid.
2. Inside the sphere x^2 + y^2 + z^2 = 16 and outside the cylinder x^2 + y^2 = 4.
 
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serg_yegi said:
1. Use polar coordinates to find the volume of the given solid.



2. Inside the sphere x^2 + y^2 + z^2 = 16 and outside the cylinder x^2 + y^2 = 4.
What have you tried? You have to show an effort first.
 
I've tried doing a double integral from theta=0 to theta=2pi and r=0 to r=4 of ((16-r^2)^(1/2))r (dr)(dtheta)
 
The limits of integration for r should be from r = 2 to r = 4. If you go from r = 0, you're getting the volume inside the cylinder, which you don't want.
 
Ok. Is the actual integral correct?
 
Yes, I don't see anything wrong with it.
 

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