Using the formula 1/f = 1/object distance + 1/image distance, in the

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In the context of two plano-convex lenses glued together, a negative image distance from the first lens indicates that the image formed is virtual. This virtual image suggests that it is located on the same side as the object, meaning it is in front of the second lens. The cemented doublet behaves as a single lens with negative power, reinforcing the virtual nature of the image. Understanding this relationship is crucial for optical applications involving lens systems. The discussion clarifies the implications of negative image distances in lens configurations.
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Using the formula 1/f = 1/object distance + 1/image distance,
in the instance where you have two plano-convex lenses glued together on their flat sides, what does it mean if your image distance from the first lens is negative? is the image in front of the second lens or behind the second lens?

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since we can consider the cemented doublet as a single lens, having d_i <0 means it is a virtual image (the doublet has negative power).
 
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