Using the momentum of the ball to find it's original height

AI Thread Summary
To determine the original height from which a 0.150 kg ball was dropped, the momentum just before landing was calculated to be 0.780 kg·m/s. The calculation involved dividing the momentum by the mass to find the velocity, resulting in 5.2 m/s. This velocity was then divided by the acceleration due to gravity (9.8 m/s²) to find the time of fall, which was approximately 0.53 seconds. Using the kinematic equation for height, the height was calculated to be 1.38 meters. The final result confirmed that the calculations were correct.
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A 0.150 kg ball is dropped from rest. If the magnitude of the ball's momentum is 0.780 kg·m/s just before it lands on the ground, from what height was it dropped?
 
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i used kg m/s / kg

.78/.15=5.2

m/s /g

5.2/9.8= .53

1/2 g (m/s /g)^2=m

1/2x9.8x.53^2=1.38

it said that i got it right
 
Last edited:

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