Good day all,
Im completely stumped on how to show this:
|AN|=(|A||N|/A intersect N|)
Here: A and N are subgroups in G and N is a normal subgroup.
I denote the order on N by |N|
Second Isomorphism Theorem
The Attempt at a Solution
Well, I know know I am supposed to use the theorem, but I have no idea where to start!
I don't seem how to relate what the theorem says to orders of sets...
Any help would be greatly appreciated!