Using the Superposition principle to solve a linear circuit

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SUMMARY

The discussion centers on applying the Superposition principle to solve a linear circuit involving resistors R1, R2, R3, and R4. The initial calculations for voltages and currents were incorrect, but the correct approach involves using the voltage divider formula and Kirchhoff's Current Law (KCL) and Kirchhoff's Voltage Law (KVL). The final results achieved were i1 = 0.5 A and i2 = 0.65 A, confirming the effectiveness of the Superposition principle when applied correctly.

PREREQUISITES
  • Understanding of the Superposition principle in circuit analysis
  • Familiarity with voltage divider circuits
  • Knowledge of Kirchhoff's Current Law (KCL)
  • Knowledge of Kirchhoff's Voltage Law (KVL)
NEXT STEPS
  • Study the Superposition theorem in linear circuit analysis
  • Learn about voltage dividers and their applications in circuits
  • Explore advanced applications of KCL and KVL in complex circuits
  • Practice solving linear circuits using simulation tools like LTspice
USEFUL FOR

Electrical engineering students, circuit designers, and anyone looking to deepen their understanding of linear circuit analysis and the Superposition principle.

Gabry89
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I tried it many times but i don't understand how to start and which are the first steps.

I started like this:

Solve for V1:

Vr1 = V1 * (R1/R1+(R2||(R3+R4))) = 5 V

I'1 = Vr1/R1 = 1 A

I'2 = I'1 * [(R1+R2)||(R3+R4)]/(R3+R4) = 0,6 A.

is that right?
 
Last edited:
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It is kinda difficult 'cause i must use the superposition.

The results should be i1= 0,5 A and i2= 0,65 A
 
Solved, it was not so difficult, anyway the formulas in the first post are wrong. You just have to be careful using the voltage divider and the KCL, KVL. The thread can be closed.
 

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