- #1

babaliaris

- 116

- 15

Hello! I'm trying to understand how this pendulum works. I found this video that explains how to calculate the T force from the rope.

He uses the preservation of kinetic and potential energy in order to find the magnitude of the velocity and then using Newton's second law, he calculates the T force.

My question is, if I understand correctly he only calculated the T in the direction of the y axis, not the x. So this is not the full answer.

In other words ##T_{y_{0}}=3mg##.

I want to know the full vector ##T = T_{x_{0}} + T_{y_{0}}## or ##T(x,y)##

Can I follow the same idea and use ΣF=ma on the x-axis? The gravity force is zero there, but what should I use for a? Maybe the tangent acceleration ##a_{T} = \frac{dV}{dt}## (where V is the magnitude of the velocity)?

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