Using Z transforms to solve difference equations.

Uan · Oct 22, 2013

Hi,

We can use Laplace transforms to solve DEs with these guys:

$Two Laplace transform identities: L{y'} = sY(s) - y(0) and L{y''} = s^2 Y(s) - sy(0) - y'(0), written as typeset equations.$

But what are the z transform versions in discrete time that include initial conditions, and how do you derive them? For example y[n+1], y[n+2] etc.

Thanks

Uan · Oct 22, 2013

As luck would have it after posting, found the answer here: https://www.physicsforums.com/showthread.php?t=493424

Time for a rest... :zzz:

Using Z transforms to solve difference equations.

Discussion

Similar threads