# Valid Units of Measure for Trig Argument

Quick question. If i pass into a trig function something like cos(3pi*15 seconds), do I drop the seconds from the resultant answer since it's not a valid unit of measure for theta?

## Answers and Replies

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that's right.
the inside of the bracket for any trig identity has units of rad (or degrees if you think that way)
it's common convention to just drop the units though, since rads aren't really a 'unit'.

jtbell
Mentor
The argument (the thing in brackets) of any trig function has to be an angle. Seconds are not valid units for angles. If in your example, the $3 \pi$ has units of radians/second, then the units would work out properly.

Integral
Staff Emeritus
Gold Member
If your problem is well expressed you will find that the factor (in your case) of 3 $\pi$ has units of 1/s . Thus you do not drop the seconds, they cancel out.

Integral said:
If your problem is well expressed you will find that the factor (in your case) of 3 $\pi$ has units of 1/s . Thus you do not drop the seconds, they cancel out.
Are radians when used in this way normally expressed per second?

jtbell
Mentor
Radians per second are the units of angular speed ($\omega$), which is a very common quantity in problems dealing with rotational motion, simple harmonic motion, and waves.

Some people prefer not to name the radians explicitly when doing units-analysis because they're not "really" units in the same sense as meters, seconds, etc. Recall that the radian is defined as the (unitless) ratio of two distances: the length along an arc of a circle divided by the radius of the circle.