Is It Possible to Independently Vary Kij in Both Methods?

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I got the result that is consist with references in fisrt case. Is there anything wrong in 2nd way?
 
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Both are wrong. In the first case you are missing a 2 in both terms (still giving the same equation if you put the variation to zero). In the second case you missed a 2 only on the first term.
 
Thank you. I see.
Kij=gimgjnKmn
I should consider another Kij here.
 
Yes, you cannot vary Kij independently of Kij.
 
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From $$0 = \delta(g^{\alpha\mu}g_{\mu\nu}) = g^{\alpha\mu} \delta g_{\mu\nu} + g_{\mu\nu} \delta g^{\alpha\mu}$$ we have $$g^{\alpha\mu} \delta g_{\mu\nu} = -g_{\mu\nu} \delta g^{\alpha\mu} \,\, . $$ Multiply both sides by ##g_{\alpha\beta}## to get $$\delta g_{\beta\nu} = -g_{\alpha\beta} g_{\mu\nu} \delta g^{\alpha\mu} \qquad(*)$$ (This is Dirac's eq. (26.9) in "GTR".) On the other hand, the variation ##\delta g^{\alpha\mu} = \bar{g}^{\alpha\mu} - g^{\alpha\mu}## should be a tensor...
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