Variational Calculus - variable density line

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SUMMARY

The discussion focuses on determining the mass distribution of small lead particles along a line of length L = (π/2)a, which is suspended in a circular arc with both ends at the same height. The required mass distribution is given by the formula ρ(y) = (M/2)(a/y²). The objective is to minimize the potential energy (U) while maintaining the specified curve shape. Participants emphasize the importance of understanding the vertical axis (y) and suggest placing the origin at one endpoint for simplification.

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  • Understanding of variational calculus principles
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  • Knowledge of mass distribution and density functions
  • Basic grasp of circular arc geometry
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  • Explore potential energy minimization in physical systems
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Orion_PKFD
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Consider a line of length [itex]L=\frac{\pi}{2}a[/itex]. We want to put small particles of lead (total mass of all particles M) in order that the line is hang in a circular arc. Both ends are at the same height. Show that the mass distribution needs to be

[itex]\rho(y)=\frac{M}{2}\frac{a}{y^2}[/itex]

This exercise if different of the "usual" from textbooks because here we know the curve, but not the density. Anyone has an ideia in order to solve this?

Best regards!
 
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What is "y" and what do you think that you should minimise? We will help you but we won't solve the problem for you.
 
"Oy" is the vertical axis. But it is reasonable that you can put the origin wherever you want. I would say that it should be helpful to place the origin in one of the endpoints.

We want to minimize the potential energy, U, but we know the shape of the curve. We need to find [itex]\rho(y)[/itex] in order that it keeps the shape (minimum U)
 

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