Various expressions for the kinetic energy

AI Thread Summary
The discussion revolves around calculating the kinetic energy of an object dropped into a hole drilled through the center of the Earth, considering the conservation of energy. The potential energy at the surface is expressed as -(GmM)/R, which should equal the kinetic energy at the center. Participants debate whether the potential energy can be considered zero at the center, with one contributor noting that as R approaches zero, the gravitational force becomes infinite. The correct expressions for kinetic energy are not directly matching the initial calculations provided. The conversation highlights the complexities of gravitational potential and kinetic energy in a theoretical scenario involving Earth's structure.
hangainlover
Messages
77
Reaction score
0

Homework Statement


Suppose that a hole is drilled through the center of Earth to the other side along its axis. A small object of mass m is dropped from rest into the hole at the surface of Earth, as shown above. If Earth is assumed to be a solid sphere of mass M and radius R and friction is assumed to be negligible, correct expressions for the kinetic energy of the mass as it passes Earth's center include which of the following?

the given choices are as follows:
a) (1/2) MgR
b) (1/2)mgR
c) (GmM)/(2R)

Homework Equations



Due to the conservation of energy, i said Potential energy = the final kinetic energy

So, on the surface of the Earth, the total potential energy = -(GmM)/R
this should equal kinetic energy




The Attempt at a Solution



I thought the answer should be (GmM)/R but none of them matches my answer.
 
Physics news on Phys.org
You assumed that the potential energy is 0 in the centre of Earth. Is it true?

ehild
 
yes cause GMm/R^2 R approaches 0
 
If R approaches 0 your expression goes to infinity.

ehild
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'Collision of a bullet on a rod-string system: query'
In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top