Vector Analysis Problem Involving Divergence

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Homework Help Overview

The discussion revolves around a vector analysis problem involving scalar functions f and g, specifically focusing on expressing a given mathematical expression as the divergence of a vector function. The original poster seeks to manipulate the expression involving gradients and Laplacians to achieve this goal.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss various manipulations of vector identities and explore the equivalence of the expression to a divergence form. Some suggest starting from the desired result to find a path to the solution, while others consider different combinations of gradients.

Discussion Status

There is an ongoing exploration of different approaches to rewrite the expression as a divergence. Some participants have provided hints and suggestions, while others express uncertainty about specific steps or concepts, indicating a productive exchange of ideas without reaching a consensus on the final solution.

Contextual Notes

Participants note the complexity of the problem and the potential need for additional identities or manipulations. There is also mention of the original poster's willingness to provide more details about their attempts if needed.

MyName
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Homework Statement


[/B]
Let f and g be scalar functions of position. Show that:
\nabla f \cdot \nabla(\nabla ^2 g)-\nabla g \cdot \nabla(\nabla ^2f)
Can be written as the divergence of some vector function given in terms of f and g.

Homework Equations


[/B]
All the identities given at https://en.wikipedia.org/wiki/Vector_calculus_identities, I suppose. Especially relevant would be the second derivative and divergence identites. Also, \nabla ^2 =\nabla \cdot \nabla

The Attempt at a Solution


[/B]
After considerable time messing around with various vector identites, I've been able to show the above is equivalent to:

\nabla \cdot (f \nabla (\nabla ^2 g)-g\nabla (\nabla ^2 f))+g(\nabla \cdot \nabla(\nabla ^2 f))-f(\nabla \cdot \nabla(\nabla ^2 g))

This is painfully close to the result I want, but I can't seem to show that the second and third terms either cancel or are themselves a divergence. I'd really like any hints, and can provide more detail as to the specific identities and manipulations I've used thus far if needed, thanks.
 
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Have you tried working it from the other end starting with the answer or is that an unknown?
 
MyName said:

Homework Statement


[/B]
Let f and g be scalar functions of position. Show that:
\nabla f \cdot \nabla(\nabla ^2 g)-\nabla g \cdot \nabla(\nabla ^2f)
Can be written as the divergence of some vector function given in terms of f and g.

Homework Equations


[/B]
All the identities given at https://en.wikipedia.org/wiki/Vector_calculus_identities, I suppose. Especially relevant would be the second derivative and divergence identites. Also, \nabla ^2 =\nabla \cdot \nabla

The Attempt at a Solution


[/B]
After considerable time messing around with various vector identites, I've been able to show the above is equivalent to:

\nabla \cdot (f \nabla (\nabla ^2 g)-g\nabla (\nabla ^2 f))+g(\nabla \cdot \nabla(\nabla ^2 f))-f(\nabla \cdot \nabla(\nabla ^2 g))

This is painfully close to the result I want, but I can't seem to show that the second and third terms either cancel or are themselves a divergence. I'd really like any hints, and can provide more detail as to the specific identities and manipulations I've used thus far if needed, thanks.

Those terms simplify to g \nabla^4 f - f \nabla^4g, which doesn't cancel.

Rather than building a vector field as a linear combination of \nabla(\nabla^2 f) and \nabla(\nabla^2 g), I would have started by building one as a linear combination of \nabla f and \nabla g.
 
Have you tried working it from the other end starting with the answer or is that an unknown?

Reference https://www.physicsforums.com/threads/vector-analysis-problem-involving-divergence.909435/

Unfortuntely the end result is unknown, otherwise that'd be a great suggestion, thanks!

Those terms simplify to g∇4f−f∇4g, which doesn't cancel. Rather than building a vector field as a linear combination of ∇(∇2f) and ∇(∇2g), I would have started by building one as a linear combination of ∇f and ∇g.

Reference https://www.physicsforums.com/threads/vector-analysis-problem-involving-divergence.909435/

Yeah, I managed to get to that simplification, which like you said defnitely doesn't cancel, so I guess I must be able to somehow write the quantity as a divergence. I'm sorry, but I don't really understand what you mean by building a vector field?

Thanks for the help so far, I appreciate it.
 
I would write,$$\nabla f \cdot\nabla\left ( \nabla^2 g\right )-\nabla g\cdot \nabla \left ( \nabla^2 f \right ) =\nabla \cdot \vec V $$
Then do the work of expanding the l.h.s. in it's spatial components and compare with the r.h.s.
 
MyName said:
Unfortuntely the end result is unknown, otherwise that'd be a great suggestion, thanks!
Yeah, I managed to get to that simplification, which like you said defnitely doesn't cancel, so I guess I must be able to somehow write the quantity as a divergence. I'm sorry, but I don't really understand what you mean by building a vector field?

Thanks for the help so far, I appreciate it.

Consider the divergence of D(g, \nabla^2 g)\nabla f - D(f, \nabla^2 f) \nabla g for some function D.
 
I would write,∇f⋅∇(∇2g)−∇g⋅∇(∇2f)=∇⋅⃗V Then do the work of expanding the l.h.s. in it's spatial components and compare with the r.h.s.

That is a great idea, thanks! I managed to solve it using this idea.
 

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