Vector Calculus World Problem About Mechanics

Click For Summary
SUMMARY

The discussion centers on a mechanics problem involving a particle constrained to move along the unit circle in the xy-plane, defined by the parametric equations (x,y,z)=(cos(t²),sin(t²),0) for t≥0. The goal is to determine the optimal release point on the circle to hit a target located at (2,0,0). The velocity vector has been calculated as (-2tsin(t²), 2tcos(t²), 0) with a speed of 2t. The key insight is recognizing that once released, the particle will follow a parabolic trajectory due to the absence of forces acting on it.

PREREQUISITES
  • Understanding of parametric equations in vector calculus
  • Knowledge of velocity and speed calculations
  • Familiarity with projectile motion and parabolic trajectories
  • Basic concepts of mechanics related to motion in a plane
NEXT STEPS
  • Study the principles of projectile motion to understand trajectory calculations
  • Learn about the implications of conservation of energy in mechanics
  • Explore the use of Lagrange multipliers for constrained motion problems
  • Investigate the effects of initial velocity on projectile paths
USEFUL FOR

Students studying physics, particularly those focusing on mechanics and vector calculus, as well as educators looking for practical examples of motion in constrained environments.

number0
Messages
102
Reaction score
0

Homework Statement



A particle is constrained to move around the unit circle in the xy plane according to the

formula (x,y,z)=(cos(t2),sin(t2),0), t[tex]\geq[/tex]0.

At what point on the circle should the particle be released to hit a target at (2,0,0)?


Homework Equations



None


The Attempt at a Solution



I computed the velocity vector and speed of the particle as functions of t:

velocity: (-2tsin(t2),2tcos(t2),0)

speed: 2t.

After wards, I got stuck. Any advice would be appreciated.
 
Physics news on Phys.org
Hint: Once the particle is released (No forces act on it), what kind of trajectory would you expect it to have? (i.e. circular, parabolic, etc.)
 

Similar threads

  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 13 ·
Replies
13
Views
3K
  • · Replies 2 ·
Replies
2
Views
1K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 20 ·
Replies
20
Views
3K
  • · Replies 2 ·
Replies
2
Views
6K
  • · Replies 5 ·
Replies
5
Views
7K
Replies
2
Views
2K
  • · Replies 29 ·
Replies
29
Views
5K
  • · Replies 12 ·
Replies
12
Views
2K