Understanding Vectors: Parallelogram PQRS Question

AI Thread Summary
The discussion centers on understanding vectors, specifically in the context of a parallelogram PQRS. The user struggles with the concepts despite reviewing class materials and educational videos. They pose a question about expressing the vector SR in terms of vectors q (PQ) and s (PS), while also seeking additional resources for learning about vectors. There is a request for links to helpful videos or materials, as the recommended textbook lacks sufficient information on the topic. The conversation highlights the challenges faced by beginners in grasping vector concepts.
recoil33
Messages
28
Reaction score
0
Hey,

I'll state first that I've obviously just been introduced to vectors and I have looked through the given material in class let alone watched "Khan Academy" and "Patrick JMT" video on Vectors but i can not really grasp the concepts.

Question:

In parallelogram PQRS let
q = PQ and
s = PS


Let U be the midpoint of SR. Extend side SR to a point T such that the length of ST is 6 times the length of SR. Write the following in terms of the vectors q and s.

When entering q and s, they won't be displayed in bold (but don't worry about that).

Q1.

SR

There are a lot more questions, just i'll see if i can get them eventually

Could someone possibly link me a video or anything on vectors?
I've tried to find some, although even the textbook reccommended doesn't even include vectors?

Thanks for the help in advance!
 
Physics news on Phys.org
Edit: I Just saw that you said you seen that video I just posted.
 
I tried to combine those 2 formulas but it didn't work. I tried using another case where there are 2 red balls and 2 blue balls only so when combining the formula I got ##\frac{(4-1)!}{2!2!}=\frac{3}{2}## which does not make sense. Is there any formula to calculate cyclic permutation of identical objects or I have to do it by listing all the possibilities? Thanks
Since ##px^9+q## is the factor, then ##x^9=\frac{-q}{p}## will be one of the roots. Let ##f(x)=27x^{18}+bx^9+70##, then: $$27\left(\frac{-q}{p}\right)^2+b\left(\frac{-q}{p}\right)+70=0$$ $$b=27 \frac{q}{p}+70 \frac{p}{q}$$ $$b=\frac{27q^2+70p^2}{pq}$$ From this expression, it looks like there is no greatest value of ##b## because increasing the value of ##p## and ##q## will also increase the value of ##b##. How to find the greatest value of ##b##? Thanks
Back
Top