# Vector field

1. Sep 25, 2008

### mite

How to plot this vector field on a graph
$$\stackrel{}{\rightarrow}$$
V=(xi+yj+zk)/$$\sqrt{}(x^2+y^2+z^2)$$

2. Sep 25, 2008

### Defennder

Well, just ask yourself if you recognise the direction the vector field is pointing along at any given coordinate. In particular, consider the position vector of that coordinate as well. Doesn't this look familiar?

3. Sep 25, 2008

### HallsofIvy

Staff Emeritus
First obvious point: For any vector field, choose some points (x,y,z) ( because you can't plot all of them!), calculate the vector at that point, and plot it.

Now, look at Defennder's post for this specific vector field. $\sqrt{x^2+ y^2+ z^2}$ is a number and affects the length of the post. How does being closer or farther away from the origin affect the length of the vector? The direction is given entirely by xi+yj+zk. What direction would that be starting at the point (x,y,z)?