Vector Kinematics: Vertical Acceleration of a Skier on a 30.0 Degree Hill

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A skier accelerating down a 30.0-degree hill at 1.80 m/s² needs to determine the vertical component of her acceleration and the time to reach the bottom from a height of 375 m. To find the vertical acceleration, trigonometric functions can be applied, specifically using the formulas Vy = VSin(a) and Vx = VCos(a). Once the vertical component is established, kinematic equations can be utilized to calculate the time taken to reach the bottom, starting from rest. The discussion also touches on the application of vectors in other scenarios, such as projectile motion, emphasizing the importance of distinguishing between velocity and force vectors. Understanding these principles is crucial for solving problems in vector kinematics effectively.
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A skier is accelerating down a 30.0 degree hill at 1.80 m/s2.

What is the vertical component of her acceleration?

How long will it take her to reach the bottom of the hill, assuming she starts from rest and accelerates uniformly, if the elevation change is 375 m
 
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What effort have you made to solve this problem?
 
I don't even understand how it should be approached
 
Draw a picture of what's going on. X and y axes and a vector from the origin going 30 degrees from the horizontal downward. Then break it into its component vectors. The one pointing down is your vertical acceleration
 
To find the vertical or horizontal component of any vector is simple trig. To break a vector into components, you usually use the formulas

Vy = VSin(a)
Vx = VCos(a)

Where a is the angle from the horizontal and V is any given vector.

Once you have the vertical component of acceleration, you're ready to solve using kinematics.

You have the acceleration, the height of the hill, and the initial velocity is 0. Which equation could you use to solve for time?
 
Oh ok...i thought that trigonometry of vectors only applies when we are dealing with velocity..sorry..thanks i got the sum...i then used the second eq of motion...
X=Vot + 1/2at2
 
homeworkboy said:
Oh ok...i thought that trigonometry of vectors only applies when we are dealing with velocity..sorry..thanks i got the sum...i then used the second eq of motion...
X=Vot + 1/2at2

Nope... Force vectors are the most common in your course. You can use vectors to describe velocity, but be sure not to mix them into your free-body diagrams.
 
i got another one

A baseball is hit with a speed of 27.0 m/s at an angle of 49.0 degrees. It lands on the flat roof of a 14.0 m tall nearby building.If the ball was hit when it was 1.4 m above the
ground, what horizontal distance does it travel before it lands on the building?
 
i found the time using t = 2Voy/g which came out to be 4.2 seconds...and then wat do i do??
 
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