Vector Notation for Work: An Exploration of Force and Displacement

AI Thread Summary
The discussion focuses on calculating work using vector notation for force and displacement. The formula for work is established as Work = F * delta x. The user initially struggles with the absence of a k component in the displacement vector but ultimately determines the displacement as 5i - 21j + 14k. After performing the calculations, they confirm the correct work done as 622 Joules. The interaction highlights the importance of understanding vector components in physics problems.
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Homework Statement


workVectors.png



Homework Equations


Work = F* delta x


The Attempt at a Solution



My thought process since the force is given in vector notations multiply the pair of i components together same applies with j and k components. However this process actually strangely does not work. And I am baffled by why a k component missing for the initial displacement.
 
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The k component happens to equal 0 at the initial position. So what?

Figure out the displacement: r2-r1
 
after substraction I get 5 i - 21 j + 14k.

5i(67i) + 23j(-21j) + 55k(14k) = 335 - 483 + 770 = 622 J <- correct! =]

thanks for the guidance, Doc Al.
 
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