- #1

jaejoon89

- 195

- 0

A = i + j + 2k

B = 2i - j + k

C = 2i - j + 4k

I took the cross product of A and B

(1, 1, 2) x (2, -1, 1) =

|i j k|

|1 1 2|

|2 -1 1|

= 3i + 3j - 3k

OK, that should be perpendicular to both vectors A and B I'm guessing...

But how do I still determine the scalars s and t -- there is only one equation!