How are these vector equations equivalent?

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SUMMARY

The vector equations (1 - t)(2i - j + 4k) + t(4i + 6j + k) and (2i - j + 4k) + t(2i + 7j - 3k) are equivalent for 0 < t < 1, as confirmed by the simplification of the left side. The equation r(t) = (1 - t)r0 + tr1 is utilized to express the linear combination of vectors. The equivalence arises from the component-wise addition of the vectors involved. Understanding this relationship is crucial for grasping vector manipulation in linear algebra.

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Homework Statement


My solutions manual states that (1 - t)(2i - j + 4k) + t(4i + 6j + k) = (2i - j + 4k) + t(2i + 7j -3k), 0 < t < 1.

Homework Equations


r(t) = (1 - t)r0 + tr1

The Attempt at a Solution


I don't see how they are equivalent. They can't be divided because one has i, j and k and the other has t.
 
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Try simplifying the left side and see what you get
 
What they wrote is just the summation of the two vectors, component-by-component. Which part don't you understand?

Chet
 

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