What is the acceleration of a falling coin?

AI Thread Summary
The discussion centers on the acceleration of a coin that falls after rolling off a balcony. The coin initially moves at a horizontal speed of 0.46 m/s and falls for 8 seconds, reaching a speed of 78.4 m/s upon impact. Participants clarify that the vertical velocity starts at 0 m/s when the coin begins to fall, emphasizing that velocity is a vector quantity. There is a suggestion for a follow-up question regarding how far from the balcony edge the coin lands, which involves understanding horizontal motion and time of fall. The conversation highlights the importance of distinguishing between horizontal and vertical components of motion in physics.
Barclay
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Missing homework template due to originally being posted in other forum.
This is not a homework question so I have posted here.
<<Mentor note: This question is homework-like and therefore belongs in the homework forums. Please also refrain from excessive use of colours and font sizes.>>

The question relates to velocity and acceleration. I think the answer of the book is incorrect.

Description: A coin is rolled along the balcony edge at the steady speed of 0.46 m/s before falling off the edge after 2.4 seconds. It then accelerates due to gravity and hits the ground after 8 seconds at a speed of 78.4 m/s. Assume that no air resistance acts on the coin.

The first part of the question asks how far the coin rolls before falling off the edge of the balcony. I got this part correct with the answer 1.1 m.

The second part asks: calculate the acceleration of the coin during its fall.

My calculation is:

upload_2014-12-29_18-2-34.png


upload_2014-12-29_18-2-34.png


upload_2014-12-29_18-2-34.png


The book just writes
upload_2014-12-29_18-2-34.png


So the book seems to have forgotten that the initial velocity of the coin was 0.46 m/s. Have they just assumed that the coin started from 0 m/s velocity or am I missing something? Please advise. Thank you
 
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Seems to me the velocity was .46 horizontally then vertically it starts at 0.
 
Barclay said:
or am I missing something?
Yes, you are. Remember that velocity is a vector.
 
Bandersnatch said:
velocity is a vector.

So that means the vertical velocity is 0m/s at onset (as jerromyjon said) and it is only the horizontal velocity that is 0.46 m/s ??
 
That's right.
 
Thanks all. This forum is great.

Don't let the "Thanks all" stop you ... keep posting if there's more to say
 
Well, if you care for a follow-up question to test your new understanding, perhaps you could try answering how far from the edge of the balcony the coin lands?
 
Bandersnatch said:
Well, if you care for a follow-up question to test your new understanding, perhaps you could try answering how far from the edge of the balcony the coin lands?

I think this is going to involve triangles, sine and cosine etc. That's beyond me at the moment. Maybe in a few months be able I'll look at this follow up question again
 
Barclay said:
I think this is going to involve triangles, sine and cosine etc. That's beyond me at the moment. Maybe in a few months be able I'll look at this follow up question again

No, you should be able to do it pretty much in your head. What is the horizontal velocity of the coin when it leaves the balcony? Does this change as it falls? How long does it fall?
 
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