Velocity of a tire rolling down the road

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Homework Help Overview

The problem involves a tire rolling along a road without slipping, focusing on the velocity of a piece of tape attached to the tire when it is at the top position relative to the road.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • Participants discuss the relationship between linear and circular motion, with some questioning the necessity of the radius for solving the problem. Others explore the concept of superposition of velocities at different points on the tire.

Discussion Status

The discussion includes various interpretations of the problem, with some participants suggesting that the velocity can be determined without the radius, while others express uncertainty about the implications of the given information. A potential direction is noted, but no consensus has been reached.

Contextual Notes

There is a noted constraint regarding the absence of the radius, which some participants believe affects their ability to solve the problem.

preluderacer
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Homework Statement


A tire is rolling along a road, without slipping, with a velocity v. A piece of tape is attached to the tire. When the tape is opposite the road (at the top of the tire), it's velocity with respect to the road is



The Attempt at a Solution



I have no idea where to even start with this. It has got me completely stumped
 
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v= \omega \times r and if it is not slipping that is all the velocity.
 
so i cannot do this problem because the radius isn't given?
 
preluderacer said:
so i cannot do this problem because the radius isn't given?

The movement of a point on the outside of the tire is the superposition of a linear movement with a speed v, and circular movement. For a point that is touching the road, the velocities cancel.
 
hi preluderacer! :wink:
preluderacer said:
so i cannot do this problem because the radius isn't given?

ah, but you know the speed of the centre of the wheel, and of the point of contact of the tyre on the ground,

sooo … ? :smile:
 
is it then 2v?
 
yup! :biggrin:
 

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