Velocity of fluid through a spherical surface

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SUMMARY

The discussion centers on calculating the speed of fluid passing through a plane normal to the vector b = -i + 2k at point P (1, 2, 4) with a fluid velocity of 2i - 3j m/s. The correct approach involves determining the unit normal vector from b, then calculating the dot product of the fluid velocity vector with this unit normal vector. The volumetric flux, defined as the normal component of velocity, is essential for this calculation. A misunderstanding of the dot product may lead to incorrect negative velocity results.

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  • Understanding of vector operations, specifically dot products
  • Familiarity with fluid dynamics concepts, particularly volumetric flux
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  • Basic understanding of three-dimensional coordinate systems
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racnna
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Fluid flows with velocity 2i - 3j m/s at point P having coordinates (1,2,4). Consider a plane through P which is normal to the vector b=-i+2k. What is the speed at which the fluid passes through the plane?

Should I do the dot product of the position vector P=[1,2,4] and b vector, then multiply this by unit vector that is in the direction of the b vector, and then dot the result with the velocity vector?? i did this and got a negative velocity! HELP
 
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racnna said:
Fluid flows with velocity 2i - 3j m/s at point P having coordinates (1,2,4). Consider a plane through P which is normal to the vector b=-i+2k. What is the speed at which the fluid passes through the plane?

Should I do the dot product of the position vector P=[1,2,4] and b vector, then multiply this by unit vector that is in the direction of the b vector, and then dot the result with the velocity vector?? i did this and got a negative velocity! HELP

The volumetric flux of fluid (volume per unit area = normal component of velocity) is equal to the velocity dotted with a unit normal to the plane.
 

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