B Velocity transformation from spherical to cartesian coords

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Transforming velocities from spherical to Cartesian coordinates requires careful consideration of the relationships between the coordinates. The correct formula for total velocity is |v| = √(dot{r}^2 + (dot{θ} r)^2 + (sin(θ) dot{φ} r)^2), which accounts for the varying radius in the latitude direction. The initial approach using Pythagorean theorem without adjusting for the sine of the angle leads to incorrect results. The confusion often arises from the complexity of the notation in resources like Wikipedia. Understanding these transformations is crucial for accurate calculations in physics and engineering contexts.
Stollaxel Stoll
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I cant't figure out how to transform ##\dot{r}##, ##\dot{\theta}##, ##\dot{\phi}## in spherical coordinates to ##\dot{x}##, ##\dot{y}##, ##\dot{z}## in cartesian coordinates (the dot is Newton's notation for the first time-derivative which is the angular velocity and velocity).

I have no trouble transforming the coordinates, but if I try ##\sqrt{\dot{r}^2+(\dot{\theta} r)^2+(\dot{\phi} r)^2}## I get the wrong total velocity if adding up the components by Pythagoras. Any ideas why this doesn't work, and even more important, how it works instead?
 
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Stollaxel Stoll said:
but if I try ##\sqrt{\dot{r}^2+(\dot{\theta} r)^2+(\dot{\phi} r)^2}## I get the wrong total velocity if adding up the components by Pythagoras. Any ideas why this doesn't work, and even more important, how it works instead?

The Wikipedia article is overloaded with unnecessary complicated notation. You just forgot to that the longitude diameter is 2πr, but the latitude diameter depends on the longitude so change your Pythagoras to ##|v| = \sqrt{\dot{r}^2+(\dot{\theta} r)^2+(sin(\theta) \dot{\phi} r)^2}##
 
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