Is the Given Force Field Conservative?

In summary, the conversation discusses verifying the conservativeness of a given force field using the determinant method and the trigonometric identity for expanding sin 2y. The conclusion is that the force is indeed conservative, as the terms in the curl cancel out. The individual should brush up on their trigonometry before continuing with further calculations.
  • #1
leroyjenkens
616
49

Homework Statement



Verify the following force field is conservative.
F = 2xcos2yi - (x2+1)sin2yj

Homework Equations



∇xF=0

The Attempt at a Solution


I'm pretty sure this is just a mistake in the book, but according to my calculations, this isn't a conservative force.
I used the determinant method to do the curl of F to find -2xsin(2y) + 4xsinycosy. Unless those two terms cancel each other to equal 0, then the force isn't conservative and there's a mistake in the book.

What do you think? Thanks.
 
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  • #2
You should brush up your HS trigonometry before doing anymore maths/physics. How do you expand sin 2y ?
 
  • #3
Oh.
Is there a way to expand sin2y manually, or is it just one of those things you have to memorize?
 
  • #4
Trigonometry generally appeals to memory even though some proofs can be visual. sin (x+y) = ? then take x=y.
 
  • #5
[tex]\sin(2y) = 2\sin y \cos y[/tex] for any angle [itex]y[/itex]. So yes, the terms cancel out and the force is conservative.
 

What is a conservative field?

A conservative field is a vector field where the circulation around any closed path is equal to zero. This means that the total work done in moving an object from one point to another is independent of the path taken.

How is a conservative field verified?

A conservative field can be verified by checking if it satisfies the necessary and sufficient conditions for conservative fields, such as the path independence and the existence of a potential function. Additionally, the curl of the field must also be equal to zero.

What are the necessary conditions for a conservative field?

The necessary conditions for a conservative field are path independence, existence of a potential function, and a curl equal to zero. These conditions ensure that the total work done in moving an object is independent of the path taken.

Can a non-conservative field be converted into a conservative field?

Yes, it is possible to convert a non-conservative field into a conservative field by adding a suitable function to the field. This is known as the method of exact differentials and is based on the fundamental theorem of calculus.

Why is verifying conservative fields important?

Verifying conservative fields is important in physics and engineering because it helps in understanding and predicting the behavior of physical systems. It also allows for the calculation of conservative integrals, which are useful in solving various real-world problems.

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