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Vertex of a parabola

  1. Dec 2, 2015 #1
    1. The problem statement, all variables and given/known data
    I'm trying to find the vertex of this parabola: y^2-12=12x

    3. The attempt at a solution
    Initially I tried to take the derivative and find the vertex by finding where it the function is zero, but apparently that does not work in this situation. Is it because it is not in standard form? I've been staring at this problem for hours. I need a hint.

    Thanks.
     
  2. jcsd
  3. Dec 2, 2015 #2

    SteamKing

    User Avatar
    Staff Emeritus
    Science Advisor
    Homework Helper

    You could have made a sketch of this equation in about 5 minutes and figured out where the vertex is located.

    Remember, since the parabola is in y2, setting dy/dx = 0 isn't going to work for finding the vertex.
     
  4. Dec 2, 2015 #3
    Ok, so I figured it out.
    It's:
    y^2=12x+12
    y^2=12(x+1)
    x=-1
    So y= 0
    I don't know why that took me so long. Math brain.
    Thanks.
     
  5. Dec 2, 2015 #4

    Mark44

    Staff: Mentor

    In future posts, please show what you have tried, rather than describe it.
     
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