Vertical Tangent Lines to an Ellipse

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SUMMARY

The discussion focuses on finding vertical tangent lines to the curve defined by the equation x² + xy + y² = 27. The derivative dy/dx is calculated as (-2x - y) / (x + 2y). The participants identify that vertical tangents occur at x = 6 and x = -6, leading to the conclusion that these x-values correspond to specific points on the curve where the tangent lines are vertical.

PREREQUISITES
  • Understanding of implicit differentiation
  • Familiarity with the concept of tangent lines in calculus
  • Knowledge of how to solve equations involving two variables
  • Basic algebraic manipulation skills
NEXT STEPS
  • Study implicit differentiation techniques in calculus
  • Learn how to find points of tangency on curves
  • Explore the geometric interpretation of vertical tangents
  • Practice solving similar equations involving curves and tangents
USEFUL FOR

Students studying calculus, particularly those focusing on curves and tangent lines, as well as educators seeking to enhance their teaching methods in this area.

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Homework Statement



Consider the curve x^2+xy+y^2=27

Homework Equations


Find all points on the curve where the lines tangent to the curve are vertical


The Attempt at a Solution


I found dy/dy = (-2x-y)/x+2y)

and I think I found the equations of lines visually to be x=6 and x=-6 but I'm not sure how to show the work.
 
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So you'll need to find what points on the curve satisfy x+2y=0...
 
oh wow i didnt realize that thanks
 

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