Very interesting incline problem

Click For Summary
SUMMARY

The discussion focuses on calculating the acceleration of a two-mass system on an incline with a friction constant of 0.2. The forces involved include the gravitational force acting on a 4 kg weight (39.2 N) and a 7 kg weight (34.3 N), along with the force of friction (11.88 N). The net force equation leads to an acceleration calculation of -0.63 m/s², indicating that the system decelerates when moving to the left due to the influence of static friction once it comes to rest.

PREREQUISITES
  • Understanding of Newton's second law of motion
  • Knowledge of forces acting on inclined planes
  • Familiarity with friction coefficients and their applications
  • Basic algebra for solving equations
NEXT STEPS
  • Study the effects of static vs. kinetic friction on inclined planes
  • Learn about the dynamics of multi-body systems in physics
  • Explore advanced topics in Newtonian mechanics
  • Investigate real-world applications of incline problems in engineering
USEFUL FOR

Students studying physics, particularly those focusing on mechanics, as well as educators looking for practical examples of force analysis on inclined planes.

jakeyboy
Messages
3
Reaction score
0

Homework Statement



Screenshot2011-06-12at115202PM.png



Find the acceleration of the system. Friction constant of incline is 0.2


Homework Equations


Force of friction = 0.2 * 7 * 9.8 * cos30 = 11.88N
Force of gravity pulling down 7kg weight = 7 * 9.8 * sin30 = 34.3N
Force of gravity pulling down 4kg weight = 4 * 9.8 = 39.2

The Attempt at a Solution



Since Fg4 > Fg7 then the system should accelerate towards the right.

Net Force = Fg4 - Fg7 - Ffriction = m4+7a

39.2 - 34.3 - 11.88 = (4+7)a
a = -0.63

It doesn't make sense that a is negative, because that would mean the system would be accelerating towards the left, and friction would change directions.
 
Physics news on Phys.org
Try to get the acceleration with the assumption that the system moves to the left. You might get a negative value again. It has sense as you assumed that the system moves when equating Ffriction =μN, that is, you used kinetic friction. Assuming that the system was in motion at the beginning, negative acceleration means that it decelerates and will stop. After it stopped, the friction is static. See if the system can be in rest assuming static friction.

ehild
 

Similar threads

  • · Replies 4 ·
Replies
4
Views
3K
Replies
1
Views
1K
  • · Replies 1 ·
Replies
1
Views
1K
Replies
6
Views
3K
  • · Replies 3 ·
Replies
3
Views
6K
  • · Replies 9 ·
Replies
9
Views
2K
Replies
10
Views
2K
Replies
4
Views
2K
Replies
6
Views
3K
Replies
3
Views
2K