Very Quick Differentiation Question

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First I attempted to ipmlicitly differentiate
c2 = a2 + b2 -2abcos(theta)

da/db


I almost got the correct solution according to MIT's key, however I missed one part. The cos from the original function remained cos, and I had differentiated it to -sin.

I'm just wondering why it remained cos instead of being differentiated?
 
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Unless theta is a function of b, then cos(theta) is a constant when trying to find the derivative with respect to b.
 
It's very difficult to read what you have written. Are those "2"s after the letters squares? If you cannot use use LaTeX, c^2= a^2+ b^2- 2ab cos(\theta), at least use "^" to indicate powers: c^2= a^2+ b^2- 2ab cos(theta).

But the real question is "differentiate what variable with respect to what other variable?"
 
Thanks, but SteamKing already helped solve my problem.. Sorry I will be sure to start using the forums code based mathematical notation from now on.
 
Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...
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