Very quick triple integral question

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SUMMARY

The forum discussion centers on evaluating the flux of the vector field v(x,y,z) = x²i + y²j + z²k using the Divergence Theorem. The user correctly identifies that the divergence of v is div(v) = 2(x + y + z). They express confusion regarding the transition to spherical coordinates, specifically whether to treat (x + y + z) as √r or to substitute the parameterized coordinates. The consensus is clear: the user must substitute the parameterized x, y, and z values to accurately evaluate the integral.

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narfarnst
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Homework Statement


Use the Divergence Theorme to evaluate the flux of v(x,y,z)=[tex]x^{2}[/tex]i+[tex]y^{2}[/tex]j+[tex]z^{2}[/tex]k on the solid T bounded above by a sphere with radius 3 and below by the xy-plane.
I've found that div(v) is 2(x+y+z).

When I go to set up the integral I get a triple integral over T of (x+y+z)dV (and I bring the 2 outside the integral). So, of course, I switch to spherical coordinates.
Now, my question. When I do the switch, can I treat (x+y+z) as sqrt(r), or do I actually have to plug in the parametrized x, y, and z and evaluate?

Thanks.
 
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hi narfarnst! :smile:

(have a square-root: √ :wink:)
narfarnst said:
… I get a triple integral over T of (x+y+z)dV (and I bring the 2 outside the integral). So, of course, I switch to spherical coordinates.
Now, my question. When I do the switch, can I treat (x+y+z) as sqrt(r), or do I actually have to plug in the parametrized x, y, and z and evaluate?

but it isn't √r ! :rolleyes:

so, yes, you do actually have to do the work! :smile:
 

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