Voltage/Current variation in a motor

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The discussion centers on the performance of a WEG asynchronous 3-phase motor operating at varying line voltages. Users note that higher line voltage (410 V) results in increased magnetizing current due to the motor approaching saturation, while lower voltage (400 V) leads to reduced current (1.35 A). It is suggested that the motor is lightly loaded since the measured currents are below the nameplate value of 1.50 A. Concerns are raised about the motor's temperature due to overvoltage conditions, and users recommend monitoring the motor's performance and temperature. The conversation emphasizes the relationship between voltage, current, and the motor's operational efficiency.
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Hi all.
I have a question.
I have a WEG asynchronous 3-phase motor, 0.55 kW (0.75 HP), 380 V, 50 Hz, cos PHI 0.82, 1410 RPM, star / Wye connected, plate current 1.50 A.
It's mounted on a conveyer belt and powered simply trough a 3-phase contactor and a Thermal Magnetic GV2ME.
In the facility, there were 410 V line voltage and I measured a line current of 1.60 A, but when later the voltage down to 400 V the current measured was 1.35 A, the current was measured by an RMS current probe.

I thougth that greater line voltage reduces the line current working near motor's nominal power, but I don't understand the measurement. Any suggestions?

rbarbali
 
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rbarbali said:
I thougth that greater line voltage reduces the line current working near motor's nominal power, but I don't understand the measurement. Any suggestions?

Your 410 volts is more than the motor's rated 380 by about 8%.

Which means you're driving its magnetic flux higher, nearer saturation
so it draws a bit more magnetizing current.

That's because of the ubiquitous B-H curve
from http://www.coolmagnetman.com/magfund07.htm
upload_2019-1-30_20-8-33.png

Since this plot has no numbers on it, we can say it's effectively amps horizontal & volts vertical

Flux will be in proportion to voltage
and once you're out past the knee it takes quite a bit more magnetizing current to push flux higher..
rbarbali said:
greater line voltage reduces the line current working near motor's nominal power,

If you drop volts low enough, the motor will begin to slow down and could even draw starting current.
That's why they burn up if you try to run them on an inadequate extension cord ..So there's a 'sweet spot' for voltage, and as you move away from it in either direction current goes up. ..

Any help?

old jim
edit PS i see Tom and i crossed in the mail again !
 

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rbarbali said:
I thougth that greater line voltage reduces the line current working near motor's nominal power, but I don't understand the measurement. Any suggestions?
That is valid if the motor is operating at constant power to the load.

p.s. That is the short answer, I see Jim gave a long version as I was typing.
 
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PS2 A curve with magnetizing current vertical and flux(and volts) horizontal,

upload_2019-1-30_20-29-15.png
 

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Thanks Jim and Tom.
I thought that the effect of the increment of the voltage over the magnetizing current was minor than I measured, but I understand, from your explanation, that the motor is going into saturation.Can we relate the effect of the voltage increment / current increment with the decrement of the power factor in the graph?

upload_2019-1-31_13-52-26.png


I can't measure the machine with 380 V (motor's nominal voltage): the present line voltage is, more or less, 400 V. From the measurement (1.60 A @ 410 V and 1.35 A @ 400V) would you tell (estimate) that the motor is not working at full load? (Working at full load, at nominal voltage 380 V, I would expect measure 1.5 A as per plate).
 

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I would estimate that as you suspect it's lightly loaded.

I say that because your current drops below nameplate between 5% and 8% overvoltage

Is my arithmetic right -
dividing your readings by nameplate values
at 7.9% overvoltage you have 6.7% overcurrent
and at 5.2% overvoltage you have 10%undercurrent
upload_2019-1-31_14-51-3.png


Is that motor running pretty hot to the touch ? Its iron is being worked fairly hard because of the overvoltage.
Find an old solenoid coil, connect it to a DMM set for AC millivolts.
Wave the coil around your motor and the meter will give you an indication of leakage flux.
Try it on days when your house voltage is running high, and when it's running low.
They'll differ because as the core moves into saturation more flux will squeeze out into the air.
If you have one of those battery "ScopeMeter" gizmos, observe the waveform. You'll see a very peaky wave, and you should notice the peaks are exaggerated on high voltage days.

Magnetics is a LOT of fun !

Any Industrial Plant is a tinkerer's paradise and such experimenting solidifies your basics - i hope your management is enlightened enough to permit it.
Write up an experiment plan and approach the boss?

old jim
 

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PS when it burns up , put in a 400 volt motor.
 
Hmmmm... a WEG you say ?
Does it have a little sticker saying it's wound with "Wise-Wire" ?
If so that's quality motor..
I found one, 30hp, in my favorite salvage yard(30 cents a pound) , bought and gave it to a friend.
Its construction was impressive.

old jim
 
Thanks Jim for your help.
I will check the temperature of the motor in a couple of weeks. Keep you informed.

Jose.
 
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