Volume of 2-sphere using triple integration (rect. cord)

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SUMMARY

The volume of a 2-sphere can be calculated using triple integration in rectangular coordinates, specifically with the equation x² + y² + z² = r². The limits for the triple integral are defined as follows: for x, the limits are from -r to r; for y, the limits are from -√(r² - x²) to √(r² - x²); and for z, the limits are from -√(r² - x² - y²) to √(r² - x² - y²). This method can be extended to higher dimensions using quadruple and quintuple integrals for 3-spheres and 4-spheres, respectively.

PREREQUISITES
  • Understanding of triple integration in calculus
  • Familiarity with spherical coordinates and their conversion to rectangular coordinates
  • Knowledge of the equation of a sphere in three dimensions
  • Basic algebraic manipulation of square roots and limits
NEXT STEPS
  • Study the application of quadruple integrals for calculating the volume of a 3-sphere
  • Learn about quintuple integrals for determining the volume of a 4-sphere
  • Explore the use of spherical coordinates in integration
  • Review examples of triple integrals in different coordinate systems
USEFUL FOR

Students studying calculus, particularly those focusing on multivariable integration, as well as educators seeking to clarify concepts related to the volume of spheres in higher dimensions.

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Homework Statement


Can anyone help me with the volume of a 2-sphere in rect cordinates? I'm having problems with the limits of the triple integral. Ultimately I will need to go beyond the 2-sphere to a 3 and 4 using quadruple and five integrals respectively. Radius at r from 0 vector.

Homework Equations



x^2+y^2+z^2+u^2=r^2

The Attempt at a Solution



So I assume the eq. is x^2+y^2+z^2=r^2
If I have x as my first and dependent interval would the limit be from -r to r?

2nd limit: -(r^2-x^2)1/2 to (r^2-x^2)1/2?

3rd limit: -(r^2-x^2-y^2)1/2 to (r^2-x^2-y^2)1/2

so then if I wanted to go to a 3 etc:

4th limit: -(r^2-x^2-y^2-u^2)1/2 to (r^2-x^2-y^2-u^2)1/2??I appreciate the help, I've been sick from class a few days and need help with the notes from class.
 
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battlebball said:
So I assume the eq. is x^2+y^2+z^2=r^2
If I have x as my first and dependent interval would the limit be from -r to r?

2nd limit: -(r^2-x^2)1/2 to (r^2-x^2)1/2?

3rd limit: -(r^2-x^2-y^2)1/2 to (r^2-x^2-y^2)1/2

If by 1st, 2nd, and 3rd limits, you mean the outer, middle, and inner limits on a dzdydx integral, then yes, those look OK.
 

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