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## Homework Statement

Any cross sectional slice of a certain solid in a plane perpendicular to the x-axis is a square with side AB, with A lying on the curve [tex]y^2 = 4x[/tex] and B on the curve [tex]x^2 = 4y[/tex]. Find the volume of the solid lying between the points of intersection of these two curves.

## Homework Equations

[tex]\int ^{b}_{a} A(x)dx[/tex]

## The Attempt at a Solution

I'm not sure if I'm going in the right direction, but so far I've put the curves in terms of y, leaving me with [tex]y = 2\sqrt{x}[/tex] and [tex]y = \frac{x^2}{4}[/tex]. After graphing, I also know that the limits of integration will be from 0 to 4 since the points of intersection are at (0, 0) and (4, 4). From here on, I'm completely lost.

Thanks :)