Volume of air for complete combustion of alkane

AI Thread Summary
The discussion centers on the calculation of oxygen volume required for the complete combustion of an alkane. The volume of oxygen is stated as 25 times 24 dm³, with the number 25 derived from the balanced chemical equation. The 24 dm³ refers to the molar volume of a gas at standard conditions. It is clarified that oxygen is consumed, not produced, during the combustion process. Understanding the balanced equation is essential for determining the correct quantities of reactants involved.
desmond iking
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Homework Statement



according to the model ans, the volime of oxygen produced is 25x 24 dm^3 ...



where does the 25 come from ??



or someone can show me other step of getting the ans ? thanks in advance!

according to the model ans, the volime of oxygen produced is 25x 24 dm^3 ...

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Isn't that just the 25 from the chemical reaction above?
The 24dm3 is probably the molar volume.
 
The 25 comes from the balanced equation on that 3rd line. Until you have the reaction equation balanced, you can't determine the quantities of each of the reagents involved.

Oxygen is not produced. Oxygen is consumed in the reaction.
 
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