Volume of Cylinders: Find V w/ Pi r2h

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    Cylinders Volume
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The volume of a cylinder is calculated using the formula V = Pi r²h. Given a diameter of 0.9 meters, the radius is determined to be 0.45 meters. Substituting the radius and height into the formula yields a volume of approximately 2.28906 m³ for a full cylinder. Since the context specifies half a cylinder, the final volume is calculated as 1.14453 m³. This confirms that the tunnel can hold 1.14453 m³ of air.
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Homework Statement


upload_2016-8-1_0-51-44.png


Homework Equations


V= Pi R2H

The Attempt at a Solution



V = Pi r2h

They gave us the radius and the height (the length can be used as height). They Diameter is 0.9 to find the radius I just divide by 2 = 0.45. So now I find the volume of the cylinder using the formula “V= Pi r2h”. V= 3.14 x 0.2035 x 3.6 = 2.28906 now we divide by 2 since its half a cylinder. So now we do 2.28906 / 2= 1.14453 m3, so the tunnel can hold 1.14453 m3 of air.
(Pretty sure I got this right just want to confirm with others.)
 
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Yes that looks right to me.
 
kk thanks
 
I tried to combine those 2 formulas but it didn't work. I tried using another case where there are 2 red balls and 2 blue balls only so when combining the formula I got ##\frac{(4-1)!}{2!2!}=\frac{3}{2}## which does not make sense. Is there any formula to calculate cyclic permutation of identical objects or I have to do it by listing all the possibilities? Thanks
Since ##px^9+q## is the factor, then ##x^9=\frac{-q}{p}## will be one of the roots. Let ##f(x)=27x^{18}+bx^9+70##, then: $$27\left(\frac{-q}{p}\right)^2+b\left(\frac{-q}{p}\right)+70=0$$ $$b=27 \frac{q}{p}+70 \frac{p}{q}$$ $$b=\frac{27q^2+70p^2}{pq}$$ From this expression, it looks like there is no greatest value of ##b## because increasing the value of ##p## and ##q## will also increase the value of ##b##. How to find the greatest value of ##b##? Thanks

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