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Volume of molecule oxygen

  1. Apr 16, 2008 #1
    1. The problem statement, all variables and given/known data
    A mass of 0.736 kg of molecular oxygen is contained in a cylinder at a pressure of 1.0 × 105 Pa and a temperature of 1°C. What volume does the gas occupy?


    2. Relevant equations

    PV=nRT

    V=nRT/P

    3. The attempt at a solution


    n=(.736)(1000)/16 = 46


    V = (46)(8.31)(274.15)/(1x10^5)

    where n = 46
    R = 8.31 J/K/mol
    T = 274.15k
    P = 1x10^5

    but that is not the correct answer, what am i doing wrong??
     
  2. jcsd
  3. Apr 16, 2008 #2

    Dick

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    Molecular oxygen is 0_2, two atoms of oxygen per molecule. That makes the molar mass 32g.
     
  4. Apr 16, 2008 #3
    so would i multiply the mass of .736(1000)32 to find the n, or basically i still am unsure of finding the n
     
  5. Apr 16, 2008 #4

    Dick

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    Multiply? You divided before and that was correct. One mole of O2 has mass 32g. So how many moles is .736kg?
     
  6. Apr 16, 2008 #5
    ahh..thanks, i got it now
     
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