(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

The base is the semicircle y = [itex]\sqrt{9-x^{2}}[/itex](Square root of 9-x^{2}.. i dont know why the formatting isnt showing up) where -3 <= x <= 3. The cross section perpendicular to the x axis are squares.

2. Relevant equations

-3[itex]\int[/itex]3 = A(y)dy

A(y) = area of cross section

3. The attempt at a solution

Okay so i know the cross section is a square. And i see that y = [itex]\sqrt{9-x^{2}}[/itex] creates a semi-circle. I am not sure how to find the cross sectional area. I'm assuming it needs to be in terms of y. And the area of a square is a (side)^{2}. But how do i know what the side is equal to?

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# Homework Help: Volume of solid with given base and cross sections

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