1. The problem statement, all variables and given/known data The area bounded by y=2 coshx, the x-axis, the y-axis, and the line x=4 is revolved about the x-axis. Find the volume of the solid generated. 2. Relevant equations I sliced the area along the axis of revolution. That is the strip is dx. So the equation necessary is pi(R^2-r^2) from the limits of integration (0,4) 3. The attempt at a solution pi[tex]\int((2cosh(x))^2-16)[/tex] from 0 to 4 I am uncertain if my logic is sound. Any feedback would be appreciated.