Volume of water flowing out a cylindrical pipe

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Homework Help Overview

The discussion revolves around calculating the volume of water flowing out of a cylindrical pipe based on its radius and the flow rate. The original poster seeks guidance on how to apply the volume formula for a cylinder to this scenario, particularly in relation to different flow rates.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the formula for the volume of a cylinder and how to incorporate the flow rate into this formula. There are questions about unit consistency, specifically whether to convert measurements from cm to m. Some participants express uncertainty about how to graph the results based on different variables.

Discussion Status

Participants have made progress in formulating the volume equations for both specified and variable flow rates. There is acknowledgment of the correctness of the graphs described, and some guidance has been provided regarding the constraints on the variables involved, such as the radius and flow rate needing to be non-negative.

Contextual Notes

There is an assumption that the original poster is working under typical homework constraints, which may limit the depth of exploration into the problem. The discussion also highlights the importance of maintaining consistent units throughout the calculations.

Jacobpm64
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Water is flowing down a cylindrical pipe of radius r.

(a) Write a formula for the volume, V, of water that emerges from the end of the pipe in one second if the water is flowing at a rate of

(i) 3 cm/sec (ii) k cm/sec

(b) Graph your answer to part (a)(ii) as a function of
(i) r, assuming k is constant
(ii) k, assuming r is constant



All right, I just don't know where to start at all... I'm thinking that I'll probably need the formula for the volume of a cylinder. Besides that, I don't know what I have to do with the formula. I'm completely clueless on how to implement the rates of water flow into the volume of a cylinder formula.. if that's even what I have to do... I'm sure that if I can figure out part (a), part (b) won't be much of a problem. (just solving for different variables and graphing)
 
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The cross area of a cylinder equals A = r^2*PI, so the volume that flows through the cylinder in one second equals V = v*A [m^3/sec], where v is the speed of water.
 
you said the volume that flows through is in m^3/sec... does that mean I have to convert to m/sec, or will the rates work if i keep them as cm/sec?

Should work as cm/sec, right?

After you respond to this.. I'm going to give it a shot, and you can let me know how I'm doing.

Thanks a lot.
 
Nope, you don't have to convert anything, of course it works perfectly well with cm^3/sec, too. I just forgot that the speed was given in cm/sec.
 
ok, let's see if i did it correctly

(a) (i) V = 3pi*r2 (where V is in cm^3/sec)
(ii) V = kpi*r2 (where V is in cm^3/sec)

(b) (i) V on the vertical axis, r on the horizontal axis. It's just a parabola .. it'll look like x2.
(ii) V is on the vertical axis, k is on the horizontal axis. It's just a linear function with a positive slope.

How's this? (and is there any way to be more specific with the graphs, like to plot out any points, even if the points are just defined as variables?)
 
Jacobpm64 said:
How's this? (and is there any way to be more specific with the graphs, like to plot out any points, even if the points are just defined as variables?)

Looks great.

The graphs are perfectly ok, and I don't see a way to be more specific than you already are, except maybe to mention that for V(r) it makes sense if r > 0, since the cylinder radius can't be negative. As for V(k), k should be greater or equal than zero, since a negative volume doesn't make any sense.
 
thanks a lot
 

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