Volume Problems: Solving for Area and Volume with Integrals

[Dick]

Sure. Estimate with rounded numbers. 200ft^3/(8*ft^3/min)=25 minutes. 5 ft/25 min=0.2ft/min roughly on average. That makes 0.15ft/min sound pretty reasonable. Not 'too small'.

 

[nns91]

Thanks for your help

 

[Dick]

Thanks for your help

Very welcome!