Watt needed to heat up an iron, correct?

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To heat an iron cube measuring 1.3cm x 1.3cm x 0.7cm, the volume is calculated as 1.183cm³, leading to a mass of approximately 9.23 grams based on iron's density of 7.8 g/cm³. Using the formula Q=mcT, with a specific heat capacity of 0.450 J/(g·K) and a temperature difference of 160°C, the total energy required is 662.4 Joules. Since 1 Joule equals 1 Watt-second, to heat the iron in 60 seconds, a power of 11.04 Watts is needed. The calculations confirm that this wattage is correct for the specified heating conditions. The discussion concludes with an affirmation of the calculations.
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an IRON cube with (Length 1.3cm Width 1.3cm Height 0.7cm) so
Volume = 1.183cm^3

density of an IRON = 7.8gm/cm^3 so
Mass = 9.2274gram

Q=mcT c for iron = 0.450 J/(g·K), T difference = 160 degree celsius
Q=9.2 . 0.45 . 160
Q=662.4Joule

1Joule = 1 Watt.second

so if i need to heat up an IRON from 20C to 180C (T difference = 160 degree celsius) in 60second

so i need (662.4/60) = 11.04Watt

correct? please advice..

thanks
 
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Yes that should be correct.
 
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