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Avg. Power

p(t)=(V^2(t))/R

My attempt at instantaneous power was

p(t,V,R)= ∫(0->1 for t ∫0->5 for V and ∫0->.1 for R V^2(t)/RdvdRdt

Integrating I go the triple integral of V^3t^2/6R^2

Substituting my values in gave a wattage of 1,250 watts/m^2 at t=1 second, v=5 volts, and R=1 ohms

Using Ohms Law V=IR or I=V/R I calculate now as I write this a current of

I=5/.1=50 amps

Is this correct?

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# Wattage delivered using triple integral help

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